A particle of mass 70 g, moving at 50 cm/s, is acted upon by a variable force opposite to its direction of motion. The force F is shown as a function of time t.
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(a, b)
The impulse given to the particle is equal to the area under the F – t graph = 0.07 kg m/s = 2 × initial momentum of the particle. Hence, the particle will reverse in direction and move with its initial speed.
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